Java Program to solve quadratic equations

Java / java programming

In this post, we will find all root of quadratic equation and print them using format() in Java.

To understand this program. we should have the knowledge of:

Java if-else statement
Java Math sqrt()

How the program will work?

if the determinant is greater than 0, the root is real and different.
if the determinant is equal to 0, the roots are real and equal.
if the determinant is less than 0, the roots are complex and different

Lets write this logic in Java Program.

Example : Program to solve quadratic equations

In this program, we will coefficients a, b, and c are set 2.3, 4, and 5.6 respectively. Then, the determinant is calculated as b² – 4ac.

Based on the above value of the determinant, the roots are calculated as given in the formula above. Notice we’ve used library function Math.sqrt() to calculate the square root of a number.

import java.util.Scanner;
public class quadratic_equations {
    public static void main(String[] args) {
        Scanner sc = new Scanner(System.in);
        double a = sc.nextDouble();
        double b = sc.nextDouble();
        double c = sc.nextDouble();
        double root1, root2;

        double determinant = b * b - 4 * a * c;

        // for real and different roots
        if(determinant > 0) {
            root1 = (-b + Math.sqrt(determinant)) / (2 * a);
            root2 = (-b - Math.sqrt(determinant)) / (2 * a);

            System.out.format("root1 = %.2f and root2 = %.2f", root1 , root2);
        }
        // Condition for real and equal roots
        else if(determinant == 0) {
            root1 = root2 = -b / (2 * a);

            System.out.format("root1 = root2 = %.2f;", root1);
        }
        // If roots are not real
        else {
            double realPart = -b / (2 *a);
            double imaginaryPart = Math.sqrt(-determinant) / (2 * a);

            System.out.format("root1 = %.2f+%.2fi and root2 = %.2f-%.2fi", realPart, imaginaryPart, realPart, imaginaryPart);
        }
    }
}

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